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a) Suppose that the weight of the adult male wombat is normally distributed with mean 8,6 pounds and standard deviation 1.1 p
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Ans: Mean (14) = 8.6 std der (6)=1.1 a) XoN(8.6, 1.1) p(+29.5)=P(x-4 x 9.5-8.6) P(280:82) - 1-P1200.82) = ) - 0.79389 - (0.20

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