mean of distribution of sample means = $221
std dev of distribution of sample means = s/√n = 62/√26= 12.159
-----------------
x bar -3s = 221 - 3*12.159 = 184.5
x bar + 3s = 221* +3*12.159 = 257.5
so, for sketch , option c) is answer
-----------------------------------
µ = 64500
σ = 5600
n= 36
left tailed
X ≤ 61500
Z = (X - µ )/(σ/√n) = -3.214
P(X ≤ 61500 ) = P(Z ≤
-3.214 ) = 0.0007 or 0.07%
so, option a) is answer
Use the Central Limit Theorem to ind the mean and standard error of the mesn of...
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