Question

Use the Central Limit Theorem to ind the mean and standard error of the mesn of the sampling distribuSon. Then sketch a graph of the sampling distributiorn The mean price of photo printers on a weosite is $221 with: standard dev ation of S82 Random samples of sze 20 are drawn from this population and the mean of each sample is determined The mean of the distribution of sample means is The standard deviation of the distribution of sample means i Type an integer or decimal rounded to three decimal places as needed. Sketch a graph of the sampling distribution. Choose the correct answer below. A. B. Ос. D. 218221224 24.6 prica(in S) Mean price n Mean price in Mean prica(in S)Find tha probabilty and intarprat the results If convanantua sachnology to tind tha probability The population mean annual salary or environmental com plance spedalists is about S04.500 A andon sample of 30 specialists is draw n from this population what is tne probability that the mean salary of the sample is less than S01.500? Assu e σ-35.000 The probability that the mean salary of the sampl i less than $81,500 ia Round to four dacimal places asneadad.) Intarpret the reaults. Choosa the comect answar balow O A. O B. 0 c, 0 D. Only 0.07% of samples of 36 specialst; wil hava a mean salary iess than se 1.500. This is an extremely unusual event. About 0.07% ofsamples of38 specialists will have a mean salery less than 1.500. This is not an unusual event. only 7% of samples or 3ฮ spesaists will have a mean salary less than S01.500 This is an extremely unusual event. About 7% of samples of 36 speciaists will have נ mean salary less tnan S61.500. This is not an unusual event.

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Answer #1

mean of distribution of sample means = $221

std dev of distribution of sample means = s/√n = 62/√26= 12.159

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x bar -3s = 221 - 3*12.159 = 184.5

x bar + 3s = 221* +3*12.159 = 257.5

so, for sketch , option c) is answer

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µ =    64500              
σ =    5600              
n=   36              
left tailed                  
X ≤    61500              
                  
Z =   (X - µ )/(σ/√n) =   -3.214          
                  
P(X ≤   61500   ) = P(Z ≤   -3.214   ) =   0.0007 or 0.07%

so, option a) is answer

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