Question

2. What is the molarity of a solution of HCl if 0.2500 L of 0.2200 M NaOH is required to neutralize .1000 L of HCI? (Use lecture notes or the theory section of the lab to help with this question.) bere

Answer 1

The balanced equation is

HCl + NaOH ----> NaCl + H2O

Number of moles of NaOH = molarity * volume of solution in L

Number of moles of NaOH = 0.2200 * 0.2500 = 0.0550 mole

from the balanced equation we can say that

1 mole of NaOH requires 1 mole of HCl so

0.0550 mole of NaOH will require

= 0.0550 mole of NaOH *(1 mole of HCl / 1 mole of NaOH)

= 0.0550 mole of HCl

molarity of HCl = number of moles of HCl / volume of solution in L

molarity of HCl = 0.0550 / 0.1000 = 0.550 M

Therefore, molarity of HCl = 0.550 M