Question

(3.29) (a) Use your calculator to find the number z such that the proportion of observations that are less than z in a standard Normal distribution is 0.32 (0.01) (b) Find the number z such that 35 % of all observations from a standard Normal distribution are greater than z. z (0.01)- (3.33) Automated manufacturing operations are quite precise but still vary, often with distributions that are close to Normal. The width in inches of slots cut by a milling machine follows approximately the N (0.8750, 0.0012) distribution The specifications allow slot widths between 0,8725 and 0,8775 inch. What proportion (+0.001) of slots meet these specifications (use software)?

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Answer #1

3.29

a) Here we want to find z such that P( Z < z) = 0.32

Let's use TI-84 calculator:

Command :  

2ND >>> VARS >>>highlight "DISTR" >>>3:invNorm( >>> Then Enter

area : 0.32

mu : 0

sigma : 1

Then highlight Paste and click on Enter

So we get the following output.

Wabbitemu File View Calculator Debug Help TI-84 Plus Silver Edition TEXAS INSTRUMENTS inYNorm (8.32.0, ト -.4676988012 STAT PL

Therefore answer is -0.47 after rounding it up to two decimal place.

b) Here we want to find z such that P( Z > z) = 0.35

This implies P(Z < z) = 1 - 0.35 = 0.65

Command :  

2ND >>> VARS >>>highlight "DISTR" >>>3:invNorm( >>> Then Enter

area : 0.65

mu : 0

sigma : 1

Then highlight Paste and click on Enter

So we get the following output.

File View Calculator Debug Help TI-84 Plus Silver Edition TEXAS INSTRUMENTS . 3853204726 STAT PLOTF1 TBLSET F2 FORMAT F3 CALC F4 TABLE F QUIT INS 2ND MODE

Therefore answer is 0.39 after rounding it up to two decimal place.

3.33

Here we want to find P( 0.8725 < X < 0.8775 )

X ~ N( 0.8750, 0.0012)

Command:

2ND >>> VARS >>>highlight "DISTR" >>>2normalcdf( >>> Then Enter

lower : 0.8725

upper: 0.8775

mu : 0.8750

sigma : 0.0012

Then highlight Paste and click on Enter

So we get the following output.

TI-84 Plus Silver Edition TEXAS INSTRUMENTS normal cdFC , 8725ト 9627792794 STAT PLOTF1 TBLSET F2 FORMAT F3 CALC F4 TABLE F

So answer of this question is 0.9628

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