Question

Prob. 2: Cooling Curve Circle: Emathermier Exothermis?) Cale, the amount of heat this time in calories (cal) - Ilse I cal 4184 for conversions) lost or removed From 1.75 mol water as steam at a convert it to solid ice chilled in a freezer to a temperature of 47.2°C Cumulative Heat Lost To do this, follow the above drawn curve to determine the amount of heat lost for each of the five steps of this process to convert superheated steam at the starting temperature to solid ice chilled to its final temperature. (Note: 4 - AH, at constant press.). Label where solidification & condensation occurs... 1. What Heat (Q) is lost in calories (cal) to convert steam at 134.0°C to steam at water's condensation point at 100.0°C. The specific heat capacity of steam is 0.4400 call( ). 2. What Heat (q) is lost from this amount of water as steam at 100.0°C to convert it to the same amount of water as a liquid at 100.0°C ? The AH.com - AH... (AH., for water is 40.67 kJ/mol or cal/mol). Use : 4.184 J-1 cal. ans. - call) 3. What Heat (q) is lost from liquid water af 100.0°C to convert it to the same amount of liquid water at its solidification point, which for water is 0.0°C. The specific heat capacity of liquid water is 1.000 cal/-"C). 4. What Heat (q) is lost from this amount of liquid water at its solidification (freezing) point of 0.0°C to convert it to ice at 0.0°C? The AH... AH.. which for water is 6.008 kJ/mol or cal/mol. Note: 4.184 J=1 cal 5. What Heat (q) is lost from Ice at 0.0"C to bring the ice to a temperature of 47.2"C? The specific heat capacity of ice is 0.4999 cali( C). 6 What is the total Heat lost or removed to convert 1.75 moles of superheated water as steam at +134.0°C to solid supercooled ice at -47.2°C? (Note the sign of or AH: if endothermie (or AH) is positive, if exothermic, q (or AH) is negative. What is the enthalpy change per mole?

Answer 1

mass of water a 1.75 mol x 18-01528 9.1 mot (steam) 231-59 lost in connecting temperature of stean msream & Ssram xor (&T: 10834) decreasing Heat L - ? 31-59 x 0.4400 cal x (134.0c Hoo-oºs). goc = - 471-63 cal ~ - 472.cat Heat lost in converting sheam to water at wort in steam xohona (-40-67x10 5/10 1.75 mol X-40-67 kJ x 185 x 4 1845 Ical mol KJ 9-184J. ah and = -9720-c -17,010-6 cal ~ -17000 cal 2 -1-70 x 104 cal. 3) Heat lost in decreasing temperature of water from woc to ooc a mocker & sand water xor ? 3 1.000 cal xt100) = - 315qocal l - 3450 cal Heat lost in converting wat liguld water o sond water at oc ho olsona 2 1.75moles G.008 KZ morkos alcat * *4-1843 2-2512-9 cal a -2510 cal Heat lost in decreasing remperature of ice 2 mcexsce Xare 2 31.59 0.4999 (all (-47-2°C) = 1744 can

so total heat rost 2 (-471-63)+€17010 6 cal) + (-31528 (an) (-2512-9 cal) + (-748 & al) 2=23, 891-59 ? - 23 900 cal cal for 7-75 - moles heat lost s 23,900 cat 새 number of moles - 23,891-59 cal 1.75 moles entraling - AH - 13,652 cal/mol 2 1 - 13,700 con/mol change here su negative as heat released (exothermic) rough graph (not a scaled graph). 346 condensation too's - sondification - - - -- - A) 472 472 cum F 231375 og gryn +1000 23,8st-36 Col (239000 42' 26624-6 712472 431526) CO cal