Every student will have a place to sit if the number of left
handers in a class of 20 are between 2 and 5
Let X be the number of left handers in a class of 20.
Probability that a random student is a left hander = 0.20
P(2 < X < 5) = P(X=2) + P(X=3) + P(X=4) + P(X=5)
P(X=2) =
20C2(0.20)2(0.80)18
Simillarly we can evaluate for X=3,4 and 5.
Summing : P(X=2) + P(X=3) + P(X=4) + P(X=5) we will have the final
answer.
#7 20% ofall students are left handed. A class of size 20 meets in a room...
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