IP A charge of 180 C is held fixed at the origin Part A Ia-6.00 C...

Question

Question

science physics

Answer 1

Answer #1

d^2 = 0.925^2 + 1.17^2

d = 1.492

using conservation of energy

kinetic energy gained = change in pE

0.5 m v^2 = k ( q1 - q2) / (d/2)

0.5* 0.003* v^2 = 9* 10^9* (18+6)* 10^-6 / ( 1.492 / 2)

v = 13893.5 m/s

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Answer 2

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