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QUESTION 1 0.5 points Save Answer A 567.6 mL sample of carbon dioxide gas, CO2, is collected at 1.41 atm and 22.3 °C. What isQUESTION 3 0.5 points Save Answer Consider the reaction between hydrogen gas and oxygen gas to form water: 2 H2(g) + O2(g) +

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Answer #1

1)

Given:

P = 1.41 atm

V = 567.6 mL

= (567.6/1000) L

= 0.5676 L

T = 22.3 oC

= (22.3+273) K

= 295.3 K

find number of moles using:

P * V = n*R*T

1.41 atm * 0.5676 L = n * 0.08206 atm.L/mol.K * 295.3 K

n = 3.303*10^-2 mol

Molar mass of CO2,

MM = 1*MM(C) + 2*MM(O)

= 1*12.01 + 2*16.0

= 44.01 g/mol

use:

mass of CO2,

m = number of mol * molar mass

= 3.303*10^-2 mol * 44.01 g/mol

= 1.454 g

Answer: 1.45 g

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