In a random sample of 600 advertisements for apartments to rent in Vancouver, 5.6% indicated that cats and dogs were allowed. In Toronto, 8.1% of all apartments for rent indicate that cats and dogs are allowed. Is Vancouver significantly less pet-friendly than Toronto? Use alpha = 0.05 and the hypotheses below.
H0: p = 0.081
HA: p < 0.081
What is the test statistic?
What is the critical value for this hypothesis test?
Test statistic

z = -2.24
Level of significance = 0.05
So,
Critical value for the left tailed test = -1.645
In a random sample of 600 advertisements for apartments to rent in Vancouver, 5.6% indicated that...
In a random sample of 84 coffee shops in Vancouver, it is found that a latte costs an average of $4.65 with a standard deviation of $0.30. Using alpha = 0.05, determine if the average price is significantly higher than $4.50. 1.Fill in the blanks to construct the correct null and alternate hypotheses. H0: [ Select ] ["p", "p-hat", "μ", "y-bar"] ...
A rental agent claims that the mean monthly rent, μ , for apartments on the east side of town is less than $700 . A random sample of 14 monthly rents for apartments on the east side has a mean of $694 , with a standard deviation of $21 . If we assume that the monthly rents for apartments on the east side are normally distributed, is there enough evidence to conclude, at the 0.05 level of significance, that μ...
Test using the p-value approach with ? = 0.05.State the null and alternative hypothesis.H0: ? < 98.6 versus Ha: ? > 98.6H0: ? = 98.6 versus Ha: ? > 98.6 H0: ? = 98.6 versus Ha: ? < 98.6H0: ? = 98.6 versus Ha: ? ≠ 98.6H0: ? ≠ 98.6 versus Ha: ? = 98.6Find the test statistic and the p-value. (Round your test statistic to two decimal places and your p-value to four decimal places.)z=p-value=State your conclusion.The p-value is greater than alpha so H0 is not rejected. There is insufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°.The p-value is less than alpha so H0 is rejected. There is sufficient evidence to...
(a)Test using the p-value approach with ? = 0.05.State the null and alternative hypothesis.H0: ? < 98.6 versus Ha: ? > 98.6H0: ? = 98.6 versus Ha: ? > 98.6 H0: ? = 98.6 versus Ha: ? < 98.6H0: ? = 98.6 versus Ha: ? ≠ 98.6H0: ? ≠ 98.6 versus Ha: ? = 98.6Find the test statistic and the p-value. (Round your test statistic to two decimal places and your p-value to four decimal places.)z=p-value=State your conclusion.The p-value is greater than alpha so H0 is not rejected. There is insufficient evidence to indicate that the average body temperature for healthy humans deviates from 98.6°.The p-value is less than alpha so H0 is rejected. There is sufficient evidence to...
Consider the following hypothesis test: Ho u-15 Ha does not equal 15. A sample of 40 provided a sample mean of 14.18. The population standard deviation is 4. Enter negative value as negative number. 1.Compute the value of the test statistic to two decimals. 2. What is the p-value (to four decimals)? Use the value of the test statistic rounded to decimal places in your calculations. 3. Using alpha = 0.05, can it be concluded that the population mean is...
A random sample is taken from a normal population. Do the hypothesis test to determine if there is evidence that the population standard deviation is greater than 5. Use a level of significance of α = 0.05. n = 25 xbar = 68.7 s = 6.2 Use the appropriate notation to show the hypotheses. H0: H1: The critical value is _________ = _______________________ The test statistic is __________= ________________________ The p value is __________________________________
Consumers with credit scores below 600 have a very difficult time getting approved for car or mortgage loans. Historically 17?% of people had a credit score below 600. Due to the recent financial? crisis, the federal government is concerned that this proportion has increased. To test this? hypothesis, a random sample of 500 people was chosen. From this? sample,102 people had credit scores less than 600. Using alpha? =0.05 a. Determine the critical value(s) of the test statistic _______________(round to...
(1 point) Family transportation costs are usually higher than most people believe. Eighteen randomly selected families in three major cities are asked to use their records to estimate a monthly figure for transportation cost. Use the data obtained and ANOVA to test whether there is a significant difference in monthly transportation costs for families living in these cities. Use a = 0.05. Edmonton 650 480 550 600 675 540 TE Toronto Vancouver 250 850 525 700 950 175 780 500...
Consumers with credit scores below 600 have a very difficult time getting approved for car or mortgage loans. Historically 29% of people had a credit score below 600. Due to the recent financial crisis, the federal government is concerned that this proportion has increased. To test this hypothesis, a random sample of 500 people was chosen. From this sample, 170 people had credit scores less than 600. Using alpha=0.10, complete parts a and b below. a. Does this sample provide...
The authors of a paper studied a random sample of 346 Twitter users. For each Twitter user in the sample, the tweets sent during a particular time period were analyzed and the Twitter user was classified into one of the following categories based on the type of messages they usually sent. Category Description IS Information sharing OC Opinions and complaints RT Random thoughts ME Me now (what I am doing now) O Other The accompanying table gives the observed counts...