Homework Answers
(4)
(a)-( 50°× 9)/5 + 32 = 112° F
(b)- (25-32)×5/9 = - 3.89 ° C
(c)- 100° C = 100 + 273.15 = 373.15 K
(d)- 40K = 40- 273.15 = - 233.15 ° C
(5)
Heat = m c ∆T = 40× 75× 1 = 3000 Calories
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