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An electron is near a positive ion of charge +9e and a negative ion of charge-8e (see the figure below). (Take a = 3.95 μm, b = 3.60 μm, and -8e 9e al Electron (a) Find the magnitude and direction of the resultant force on the electron. (Let right be the +x-direction. Measure the angle counter- clockwise from the +x-axis.) magnitude direction (b) Find the magnitude and direction of the electrons instantaneous acceleration (Let right be the +x-direction. Measure the angle counter-clockwise from the +x-axis.) magnitude direction

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Thanks for asking ..0 = 60-6° a = 3.95um 3Mm b=3•6 Mm a F2 +9e Fi = 9X16?x8x{16XidJ² (2x156)2 Fi=2.048X10N Fi %3D 9x6? x g (1-6XE!9]² -16 =1.329

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