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The potential energy of a particle = 3x2y (Joules). What is the x-component of the force...

The potential energy of a particle = 3x2y (Joules). What is the x-component of the force on the particle if it is placed at location of (2 m, 6 m)?

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given u= 3x2 y = 6x4 x-component of the force F = - du = -2 / Loxy) = - by Ę at (2m, 6m) is F = -6(6m) = -3657

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