Question

chem

student mixes 25.00mL of 0.1000M nitric acid with 40.00mL of 0.05OOM potassium 3. A stude ide solution. What substances will be present in the final solution, and what will the molarities be? 4. A student dispenses 25.66mL of 0.1034M HCl into a 250mL Erlenmeyer flask, adds 4 drops of phenolphthalein and then adds 33.05mL of 0.1007M NaOH solution. What color is the lution? Why?

Answer 1

3. kot + HNO KOHT - KNO3 H₂O rol of two = 25 ml. molarity its ANO 0.1M. no. d moles of HNO - ndarity & volume (2) = 0.1 x 25 1000 = 205 milli moles. In the similar way. moles it koll = no x 0.05 = 2 milli moles. So, I mole of but we have 190t requires 1 mole do two.. nog in excess. NO - KOH - TANO & H₂O In final solution 2 millimolo ds KNO, 2 milli mole ds to and of milli mole & 16 Ang is present No. Tolal vol. = 25 two mi = 65 ml. & Molarity is teNo - moles is no Carity of KNO₃ = 1 vol = 0.5 mm - 7.69x10 m = 6.5 mm 65 m) = 0.031 M - Molarity in H₂O - 2 Ź -0.031 M -0.03M

Hal & NaoH - Nail & Ho - In the similar way moles at tel – I as previous, Molarity vol. - 0.1034 x 25.66 mi 2.653 indle. s moles of Naot = molarity xvol. 0.1007 x 83.65 ml 3. 328 nmole. mole des each reactants reacts. But Nach is excess in number. So, the final Solection Contains excess taotin St. .. present in pink Colour phenolphthalein is in basic medium. Thats the final Solution is Pink in colocar. mo