Question

In Figure P3.46, the line segment represents a path from the point with position vector 15 i^ + 3 j^ 2 m to the point with location (16 i^ + 12 j^) m. Point is along this path, a fraction f of the way to the destination. (a) Find the position vector of point in terms of f. (b) Evaluate the expression from part (a) for f = 0. (c) Explain whether the result in part (b) is reasonable. (d) Evaluate the expression for f = 1. (e) Explain whether the result in part (d) is reasonable.

(16, 12) (5. 3) Figure P3.46 Point is a fraction fof the distance from the ini- tial point (5, 3) to the final point (16, 12).

Answer 1

t of Horizontal position of point A must be fraction the destination x= 5m + f(16m-5m) =(5+11f)m similarly vertical position 4= 3m ++ (12-3) = (3+94) m so position rector of A = 15+11 f) it 13+9+) Î

1. position vector of A for fro letter c) As eu position relich is le that means case of fão we got the vector of first point itself due to tão factor towards destination is z ero point A lies ou starting poin fat Position vector of A for = 15+11)i + 13+9) = 168 + 129 e) - of As the fall A same we as will get destination position vector point which reasonable