Question

Internal Energy of a gas, ldeal Gas Law 1. The average kinetic energy of a molecule, is called thermal energy, it is directly related to absolute temperature. 1 3 KE (average per molecule) mv(average) =kT (kg =1.38x10-23 J/K) 3KBT 2. The average speed of molecules in a gas: vrms+ т where vrms stands for root-mean-square (rms) speed. 3. The INTERNAL ENERGY of a gas is the TOTAL ENERGY of ALL the N atoms and molecules For a MONATOMIC gas, each atom (molecule) has only the kinetic energy. Therefore, 3 Internal Energy U N KE (average per molecule) =N kT) = -NkgT= nRT 2 2 3PV NkgT = nRT, then Internal Energy U = 2 Use the ideal gas Law: PV (a) What is the average kinetic energy of a gas molecule at 19 °C? Report result in 1023 J. For example, if the result is 736*1023 J, enter 736 10A-23 J 6.08 Incorrect (0.0%)

Answer 1

Page No. Date And can average Kinett'c Energy at 19c. T = 19 = 292 K, R= 138 X10 TK so O K.E. (Arg) = 27 KAT 23 = 3x138 X16X292 38 X30 X 232 Kit = 604.44 X 10 J (6) n=3.2 moles , T=19c =292k R=8.314 J/molk U = 3 NRT 3.2 X 8.314 X 292 U = 11652.9024 J Volume = V = 0.0024 mo Pressure=p=7x105 Pa Internal Energy U=3pv U = 3 X 7 X10 X 0.0 U- 3x7x10 X0.0024 U= 2520J To=19 C = 292R Then

Page No. Date Then average sheed Vovo = 3K 0 if arg. speed is triplet, then Varg = 3 X Vaug. Tag = 3X BKT m 813KB X IT 3 KB X GT m T'=9T T = 9X 292 T'=2628K oc we have to calculate it in so T'- 2628-273 T! - 2355 So, The final tempsetwee would be 2355°C
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