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10 8.rOIL0 sa5ip aueyjubis jo Jaqunu pauoo aua sey JaMSue Jnok auns ag
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Answer #1

O=mcat Energy a = amount of c= specific heat M = mass AT = Tfinal – Tinitial Here we have - m=462-0 mg = 0.462 g { lng= 0.001

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10 8.rOIL0 "sa5ip aueyjubis jo Jaqunu pauoo aua sey JaMSue Jnok auns ag
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