Question

Verizon 11:00 PM 19%D Question 6 of 10 Submit Determine the number of molecules of Cr2O3 that form when 1.34 x 103 g of oxygen completely reacts according to the following equation: 4 Cr(s) + 3 02(g) → 2 Cr2O3(s) 4 meter 1.34 x 103 sor 3 STARTING AMOUNT 4 mol Cr 2 mol Cros - 1.68 x 103 molecules Cryo, 1.34 x 10° 0 x *3 g 02 * 1 mol Cr ADD FACTOR DELETE ANSWER RESET 1.34 x 103 4.24 x 103 g Cr 2 52.00 2.52 x 1025 mol Cr N| دی 32.00 3.78 x 1025 g 02 152.00 mol O2 6.022 x 1023 1.68 x 1025 g Cr2O,

Answer 1

Suestion - 6 : Here the given balanced equatic on 4 Cro (5) +3 0₂ (9) 2 CO₂ (s) Molar mass of oxygen asteen = 2 x 16 g/md_32 g/mol Molan mass of Croz is = 152 g/mol In the above equation we can See that 2 mol of of reacts to prooduce 2 mol of co oz. Thus, froom - 2x32 g Og we get 2 x 152 g ano 2x 152 7 " 3x30 1:34 x 103. - .. 2x152 x 1-348103 3x32 g na = 4.24 x 103 g ano

Now, 152 g Cn Oz = 1 mol Cro Oz 23 = 6.022 x 10 molecule of molecule of Ch 03 algo = 6.022 x 1023 152 . 4. 24 x 100 g roz = 6:022 x 18 x 4.24 x 10² 152 molecule of Crooz = 1.68 x 1025 molecule of Croa 8. Number of molecules that form = 1.68 x 1025