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A soccer ball is kicked with a speed of 18.0 m/s at an angle of 30.0...

A soccer ball is kicked with a speed of 18.0 m/s at an angle of 30.0 ∘ above the horizontal. If the ball lands at the same level from which it was kicked, for what amount of time was it in the air?

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Answer #1

time of flight = 2u sin a / g

where u = initial velocity

a = angle of projection

g = acceleration due to gravity

t = 2*18*sin 30 / 9.8

= 1.84 s

so the ball remains for 1.84 s in the air

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