Question

5. The decomposition of ozone is important to many atmospheric reactions:

O₃(g) à O₂(g) + O(g)

A study of the kinetics of the reaction resulted in the following data:

Temperature (K)	Rate Constant (M-1·s-1)	Temperature (K)	Rate Constant (M-1·s-1)
600	3.37 x 103	1300	7.83 x 107
700	4.85 x 104	1400	1.45 x 108
800	3.58 x 105	1500	2.46 x 108
900	1.70 x 106	1600	3.93 x 108
1000	5.90 x 106	1700	5.93 x 108
1100	1.63 x 107	1800	8.55 x 108
1200	3.81 x 107	1900	1.19 x 109

	Determine by graphical analysis the Ea for the reaction (using EXCEL) by plotting ln k vs. 1/T. Be sure to attach a copy of the EXCEL graph with your assignment. Determine the rate constant, k at 298 K (Show work!)

Answer 1

Temperature(K)	rate costant	1/T	lnK
600	3370	0.00166667	8.122668
700	48500	0.00142857	10.78932
800	358000	0.00125	12.78829
900	1700000	0.00111111	14.34614
1000	5900000	0.001	15.59046
1100	16300000	0.00090909	16.60668
1200	38100000	0.00083333	17.45572
1300	78300000	0.00076923	18.17606
1400	145000000	0.00071429	18.79224
1500	246000000	0.00066667	19.32084
1600	393000000	0.000625	19.78932
1700	593000000	0.00058824	20.2007
1800	855000000	0.00055556	20.56661
1900	1190000000	0.00052632	20.89722

InK Vs. 1/T Ink у = -11201x + 26.79 0.0005 0.0015 0.002 0.001 1/T

constant are ctivation Related energy my the anel Rate equation dimke © c/ - Yiels link = -tal tina y = mater using this equation no By plotting the graph Blw Ink / 1/7 we get Hope = - Ea / that will help to find Ea from greeph Y = -1/2012 +26179 slope = 411201 = tem (former C) Eu=11201 XR Ea = 1/2018 8.3145 J/mol Eu= 931251114 Il mol Ea= 93.125 kJ/moll

Rate constant at 298 = 0 Ti= 2988 T2 2 600 Kz = 3.37 *103 In All - Euro 1 - 2 - 7) frem equcetren Rey puting liners In the price - 1120) x B (to tys) 11201 (298-600 ) 3.37X103 600x298 im K -81.918 3.37%),3 e-81.918 1.37x13 - ki = 0.0000000061 X 3.37 X103 K = 0.0000 204762 Iki = 2.04 x 65 Temist)