Question

P-? theta Problem #9 What is the power in horsepower (hp) necessary to keep a car with of 1.200 kg constant angle 13 degrees (ignore air resistance) going at a constant speed (v) of 54 mph (24 m/s) up a hill of Enter value of the power in hp: (or type E to end): |

Answer 1

"DATA: - (m) = (1200 kg) (v) = (24 m/sec) (theta) = (13 degree) (p) = ? (in H. P) - we know that [power (p)] = (F. V) rightarrow (i) [where (F) = [force in Newton's] (v) = [velocity in m/sec]] Here, (v) = (24 m/sec) (F) = ? (p) = ? Now, ""F"" has to be find out in order to find ""p"" By newton�s II law of motion, we have, (F) = (ma) rightarrow (ii) [where (M) = (mass in kg) (F) = (force in N) (a) = [acceleration in m/s^2]] Here, (M) = (1200 kg) (a) (g sin theta) (g) = (9.8 m/s^2) (theta) = 913 degree) (F) = ? [because for an inclined plane, (acceleration) = (g sin theta) (theta) = [angle of in] (g) = [9.8 m/s^2 (therefore constant)] \r\n therefore rightarrow (F) = [(1200) (9.8) sin (13 degree) kg - m/s^2] "