Question

Oxalic acid, H2C204, is used in the restoration of old wood. What is the molarity of oxalic acid if 29.78 mL of 0.538 M NaOH is required to titrate a 14.75 mL of an oxalic acid solution given the following reaction? (3 decimal places, fill in the number ONLY!) H2C2O4 (aq) + 2 NaOH (aq) → Na2C204 (aq) + 2 H20 (1)

Answer 1

The general reaction of oxalic acid and NaOH is as follows:

H2C2O4 (aq) + 2 NaOH = Na2C2O4 (aq) + 2 H2O(l)

Number of mole s= molarity * volume in L

= 0.538 mole / L * 29.78 ml *1 L /1000 ML

= 0.01602 Moles NaOH

Now calculate the moles of acid as follows:

0.01602 Moles NaOH*1 mole H2C2O4 /2 Moles NaOH

= 0.00801 Moles H2C2O4

Molarity = number of moles / volume in L

= 0.00801 Moles H2C2O4/14.75ml /1 L/1000 ml

= 0.543 M or mole s/ L