Question

i just wanted to to check my work for the experimental ka of acetic acid .

is my experimental ka correct?

Since the titration with l-mL increments is done to give a rough estimate of the point, you need report on only the results from the more precise increment titra ents is done to give a rough estimate of the equivalence Acetic Acid Literature value for K, of Acetic Acid 1.8 X 10 (p.) Literature value for pK, of Acetic Acid Volume of base to reach equivalence point pH at equivalence point Volume of base halfway to equivalence point pH at halfway to equivalence point Experimental pK, of Acetic Acid Percent error of PK Experimental K, of Acetic Acid 4.75 27.1 8.00 13.5 4.05 4.05_15 pers.) 14.7% 1. 12x10 is pes) 522.2% Percent error of K how both percent error calculations (4 pts.): 4.75 -4.0 173 -14 11.8x103-1, 120109 1 1.8x10-5 I 4.75 DAD Unknown code "olume of base to reach equivalence point 755 H at equivalence point 10.55 olume of base halfway to equivalence point

Answer 1

Ans: :: We know._ at half of_equivalence pocnt .. pH = pka + log Charles But cancie) = 1 --- So pH = Pk a at this poent _so_pka of CH3COOH = 4:05. percentuerinon_= accepted valere - experimentvalue XIOO- accepted value - 4.75 -4.05 X-100% .4.75 = 14.34 14.7). - Now pka .= -log ka Soka =__Antilog (pka). _Antèlog (34:05.)_ = 10 ea Scanned daith- 28.918.10-5 » 8.9.X.10-5 . CamScanner (expeлiм еnfоr Ka) 64.05)

Literature value fox ka of CH2COOH = 1:8-X 10 pencent error of KQ 1P 8.9x10-5.-1.8.9 X 105. 1.8. X10-5 . = 394:4_9%. Your experce mental ka calculation has __been slightly wrong es Started with CamScanner