Ho : µ1 - µ2 = 0
Ha : µ1-µ2 < 0
Level of Significance , α =
0.05
Sample #1 ----> 1
mean of sample 1, x̅1= 14.90
standard deviation of sample 1, s1 =
5.4
size of sample 1, n1= 900
Sample #2 ----> 2
mean of sample 2, x̅2= 46.500
standard deviation of sample 2, s2 =
11.70
size of sample 2, n2= 905
difference in sample means = x̅1-x̅2 =
14.900 - 46.5000 =
-31.6000
std error , SE = √(s1²/n1+s2²/n2) =
0.4286
t-statistic = ((x̅1-x̅2)-µd)/SE = (
-31.6000 / 0.4286 )
= -73.7361
Degree of freedom, = 1273
\p-value = 0.0000 [
excel function: =T.DIST(t stat,df) ]
Conclusion: p-value<α , Reject null
hypothesis
There is enough evidence to support the claim
4. The following table summarizes the sucrose consumption (mg in 30 min) of black blowflies injected...