An electrochemical cell involves the Au3+/Au and the acidic MnO4-/Mn2+ half-cells. For standard conditions, the anode is the gold cell. Calculate the pH (to two decimal places) required to make the gold cell the cathode. Assume an Ecell of 0.01 V.
E (Au +) = 1.42V
E (8H+ +MnO4-) = 1.55V


An electrochemical cell involves the Au3+/Au and the acidic MnO4-/Mn2+ half-cells. For standard conditions, the anode...
The cell potential of the following electrochemical cell depends on the gold concentration in the cathode half-cell: Pt(s)|H2(g,1atm)|H+(aq,1.0M)||Au3+(aq,?M)|Au(s). What is the concentration of Au3+ in the solution if Ecell is 1.26 V ? To what pH should you adjust a standard hydrogen electrode to get an electrode potential of -0.117 V ? (Assume that the partial pressure of hydrogen gas remains at 1 atm.) Express your answer using two decimal places.
4. Calculate the cell potential for the half cells Fe3+/Fe2+ and MnO4- /Mn2+, where the Mn process occurs at the cathode, under the following conditions and predict whether the reaction is spontaneous: [Fe3+] = 1.0 M, [Fe2+] = 0.1 M, [MnO4 - ] = 0.01 M [Mn2+] = 1 x 10-4 M [H+ ] = 1 x 10-3 M Fe3+ + e− → Fe2+ +0.700 V MnO4 − (aq) + 8 H+ (aq)+ 5e− → Mn2+ (aq) + 4 H2O(l)...
A galvanic cell is prepared using the following half-cells: (i) MnO4-(0.283M), Mn2+(0.081M), and H+(1.0 M), and (ii) Sn2+(0.236M) and Sn4+(0.145M). MnO4-+ 8H++ 5e-↔Mn2++ 4H2O Eo= 1.507 V Sn4++ 2e-↔Sn2+Eo= 0.151 V a)Calculate the galvanic cell voltage. b)Write the complete cell description. c)Write the cell reaction indicating clearly the direction of spontaneous reaction. d)Name the electrode (anode or cathode), give the polarity (positive or negative) of the electrode, and state the reaction (oxidation or reduction) occurring in the tin half-cell. Please...
A voltaic electrochemical cell is constructed in which the anode is a Mn2+ |Mn half cell and the cathode is a Pb2+ |Pb half cell. The half-cell compartments are connected by a salt bridge. Write the anode reaction. Write the cathode reaction. Write the net cell reaction. In the external circuit, electrons migrate _____fromto the Mn2+ | Mn electrode _____fromto the Pb2+ |Pb electrode. In the salt bridge, anions migrate _____fromto the Mn2+ | Mn compartment _____fromto the Pb2+ |Pb...
20;. The cell potential of the following electrochemical cell depends on the gold concentration in the cathode half-cell: Pt(s) | H2(g,1atm) | H+(aq,1.0M) | Au3+(aq,?M) | Au(s). What is the concentration of Au3+ in the solution if Ecell is 1.22 V ? Express your answer using two significant figures. [Au3+] = ______ M
The cell potential of the following electrochemical cell depends on the gold concentration in the cathode half-cell: Pt(s)|H2(g,1atm)|H+(aq,1.0M)|Au3+(aq,?M)|Au(s). What is the concentration of Au3+ in the solution if Ecell is 1.257 V ? Express your answer using three significant figures and in fM (f = femto = 10-15).
The cell potential of the following electrochemical cell depends on the gold concentration in the cathode half-cell: Pt(s) | H2(g,1.0bar) | H+(aq,1.0mol L−1) | Au3+(aq,?mol L−1) | Au(s) What is the concentration of Au3+ in the solution if Ecell is 1.22 V ? Express your answer using two significant figures.
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A galvanic cell is prepared using the following two half-cells: (i) MnO4 (0.273 M), Mn2+ (0.167 M), and H+ (1.0 M), and (ii) Fe2+ (0.247 M) and Fe3+ (0.389 M). The standard reduction potentials for the two half cells are: Mnoa + 8H+ + 5e – Mn2+ + 4H20 E° = 1.507 V Fe3+ + e- Fe2+ E° = 0.770 V a) Calculate the voltage for this galvanic cell. b) Write the balanced equation for...
The cell potential of the following electrochemical cell depends on the gold concentration in the cathode half-cell: Pt($)|H2(9, 1.0 bar) H+ (aq, 1.0 mol L-Aus+ (aq,? mol L-)|Au(s). Part A What is the concentration of Au3+ in the solution if Ecell is 1.23 V ? Express your answer using two significant figures. YO ALC * * O O ? Au3+1 = mol L-1 Submit Request Answer
1) Suppose that gold and silver half-cells are suitably connected. Au+3 + 3e- --> Au(s) E° = +1.50 v Ag+ + 1e- --> Ag(s) E° = +0.80 v a. i. indicate the cathode and anode half-reactions ii. Write the overall cell reaction iii. Calculate E° for the cell