Data from a small bookstore are shown in the accompanying table. The manager wants to predict Sales from Number of Sales People Working. Complete parts a through h below.
|
Number of sales people working |
Sales (in $1000) |
|
|---|---|---|
|
3 |
10 |
|
|
4 |
11 |
|
|
5 |
13 |
|
|
9 |
15 |
|
|
11 |
18 |
|
|
11 |
20 |
|
|
12 |
20 |
|
|
14 |
23 |
|
|
17 |
23 |
|
|
20 |
25 |
|
|
x overbar x=10.6 |
y overbar y=17.8 |
|
|
SD(x)=5.56 |
SD(y)=5.31 |
|
a) Find the slope estimate, b1.
b1=???? (Round to two decimal places as needed.)
Solution:
The formula for slope is given as below:
Slope = b1 = r*(Sy/Sx)
We are given Sy = 5.31
And Sx = 5.56
Now, we have to find the value for the correlation coefficient r. The formula for the correlation coefficient is given as below:
Correlation coefficient = r = [n∑xy - ∑x∑y]/sqrt[(n∑x^2 – (∑x)^2)*(n∑y^2 – (∑y)^2)]
The calculation table for the correlation coefficient is given as below:
| .S no. | X | Y | XY | X^2 | Y^2 |
| 1 | 3 | 10 | 30 | 9 | 100 |
| 2 | 4 | 11 | 44 | 16 | 121 |
| 3 | 5 | 13 | 65 | 25 | 169 |
| 4 | 9 | 15 | 135 | 81 | 225 |
| 5 | 11 | 18 | 198 | 121 | 324 |
| 6 | 11 | 20 | 220 | 121 | 400 |
| 7 | 12 | 20 | 240 | 144 | 400 |
| 8 | 14 | 23 | 322 | 196 | 529 |
| 9 | 17 | 23 | 391 | 289 | 529 |
| 10 | 20 | 25 | 500 | 400 | 625 |
| Total | 106 | 178 | 2145 | 1402 | 3422 |
Correlation coefficient = r = 0.971733 Correlation coefficient = r
= [10*2145 – 106*178]/sqrt[(10*1402– 106*106)*(10*3422 –
178*178)]
Slope = b1 = r*(Sy/Sx)
Slope = b1 = 0.971733*(5.31/5.56) = 0.928039
Required answer: b1 = 0.928039
Data from a small bookstore are shown in the accompanying table. The manager wants to predict...
Data from a small bookstore are shown in the accompanying table. The manager wants to predict Sales from Number of Sales People Working. Complete parts a through h below Data Table Number of salesSales (in $1000) 10 12 14 15 18 20 20 24 24 26 y 18.3 SD(y) = 5.46 4 10 10 13 15 15 18 x-10.2 SD(x)-5.37 |
please show work
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