Question

Standard Entropy Hydrocarbons containing halogens are very useful molecules in synthetic chemistry. Calculate Sº for the reaction product in the equation shown below if ASº for the reaction is -133.0 3 K. C2H4(9) + Br2(g) + CH2BrCH2Br(9) See appendices to your text for the needed thermodynamic data. 238.5 J/K/mol The data required is found in Appendix Four, PA19-A21 of Zumdahl, Chemical Principles 8th ed.

Answer 1

Equation: C,H. (g) + Br2(g) → → CH,BrCH,Br(8) Standard entropy change of the reaction is, Asn= ms" (products) - nS" (reactants) Aso (1x${CCH,BCHEN(81) * 1 - (1xsecu() +1%82.c))] -133.0JK = ((1 mol X580,20301.00)-1 +1 mol x 245.35 Jmol.K )) 1 mol 219.20 J/mol.K - 133.0J/K = ((1 mol XS:, ACH,#2)-(219.20 JK +245.35 JK)) -133.0J/K = (1 mol X SECH,SACH,A(8) - 464.55 JIK 1 mol x SCH,BACHBr(s)) = -133.0J/K + 464.55 JXK = 331.55 J/K (CH BCH B{5)) = 331.55 – mol. K