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Consider the following data for questions A-F: Two solutions of an unknown slightly soluble salt, A(OH),, were allowed to equ
Calculate the Gibbs free energy (in kJ/mol) at 25 °C. 150 AZ¢ * * O O ? kJ/mol
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Answer #1

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At 25oC, we have, Ksp = 1.94 x 10-4

Also, universal gas constant, R= 8.314 J/K.mol

Temperature, T=25oC=25+273 K=298 K.

Therefore, Gibbs free energy is given by,

AG = -RT In K = -8.314 J/K.mol x 298 K x In(1.94 x 10-4)

:: AG = 21177.73 J/mol

We have,1 J = 10-3 kJ

:: AG = 21177.73 x 10-3 kJ/mol

:: AG = 21.18 kJ/mol


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