Question

QUESTION 10 To faciliate post-experiment data analysis, is is important to determine the limiting reagent in the salicylic acid synthesis. Assume that all 4.0 mL of methyl salicylate was placed in the beaker and reacted, that most of the NAOH solution is water, and that the total water used is 56 mL. The density of Tnethyl salicylate is 1.18 g/mL and the density of water is 1.00 g/mL. Pay close attention to units and dimensional analysis when cômpleting this problem. If methyl salicylate reacted with an excess of water, how many moles of salicylic acid can be produced from 4.0 mL of methyl salicylate (m.s.)? QUESTION 11 To faciliate post-experiment data analysis, is is important to determine the limiting reagent in the salicylic acid synthesis. Assume that all 4.0 mL of methyl salicylate was placed in the beaker and reacted, that most of the NaOH solution is water, and that the total water used is 56 mL. The density of methyl salicylate is 1.18 g/mL and the density of water is 1.00 g/mL. Pay close attention to units and dimensional analysis when completing this problem. If water reacted with an excess of methyl salicylate (m.s.), how many moles of salicylic acid can be produced from 56 mL of water?

Answer 1

Q10. moles of salicylic acid produced = 0.031

Q11. moles of salicylic acid produced = 3.1

Explanation

Q10. volume methyl salicylate = 4.0 mL

mass methyl salicylate = (volume methyl salicylate) * (density methyl salicylate)

mass methyl salicylate = (4.0 mL) * (1.18 g/mL)

mass methyl salicylate = 4.72 g

moles methyl salicylate = (mass methyl salicylate) / (molar mass methyl salicylate)

moles methyl salicylate = (4.72 g) / (152.15 g/mol)

moles methyl salicylate = 0.031 mol

moles salicylic acid formed = moles methyl salicylate consumed

moles salicylic acid formed = 0.031 mol