(1 point) If P(A) = 0.1, P(B) = 0.1, and P(AUB) = 0.2, then P(An B)...

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Question

math Statistics-And-Probability

Answer 1

Answer #1

Given P(A) = 0.1 P(B) = 0.1 P(AUB) = 0.2

We know that P(AUB) = P(A) + P(B) - P(ANB)

P(ANB) = 0.1 +0.1 -0.2 = 0

For two events A and B, to be mutually exclusive, PAB) = 0

For two events A and B, to be independent, P(ANB) = P(A.P(B)

Here PAB) = 0 but P(ANB) + P(A.P(B)

A and B are mutually exclusive but not independent

Answer 2

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