Question

[2] Your answer is partially correct. Try again. An electrically neutral model airplane is flying in a horizontal circle on a 3.5-m guideline, which is nearly parallel to the ground. The line breaks when the kinetic energy of the plane is 50 1. Reconsider the same situation, except that now there is a point charge of +q on the plane and a point charge of -q at the other end of the quideline. In this case, the line breaks when the kinetic energy of the plane is 52.0 J. Find the magnitude of the charges 2.8e-5

Answer 1

Solution :- Given data:-

kinetic energy is mv²/2 =52 J

           k is constant = 9*10^9 Nm²/C²
            q1and q2 are the charge of the particles
circular radius = 3.5 m
         since q₁= q₂ =q

    when a particle is moving in a horizontal circle its centrifugal force is equivalent to electrostatic force between particle and the particle at the center
       so
q192

         by multiplying with 1/2 on both sides and cancelling the r in the denominator
                  
1 29142

52. = [(9×10^9)×(q^2)]÷[2×3.5]

q = 2.011× 10^-4 Columbus.