determine the [oh] of a solution with a PH of 5.40 PRACTICE – DETERMINE THE [OH-]...

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Question

determine the [oh] of a solution with a PH of 5.40

science chemistry

Answer 1

Answer #1

Given : pH = 5.40

We have relation, pH = - log [ H ⁺ ]

$\therefore$ 5.40 = - log [ H ⁺ ]

Taking anti log on both sides , we get

[ H ⁺ ] = 10 ^-5.40 = 3.98 $\times$ 10 ^-06 M

We have relation, [ H ⁺ ] [ OH ^- ] = K w = 10 ^-14

$\therefore$ [ OH ^- ] = 10 ^-14 / [ H ⁺ ] = 10 ^-14 / 3.98 $\times$ 10 ^-06 = 2.51 $\times$ 10 ^-09 M

ANSWER : [ OH ^- ] = 2.51 $\times$ 10 ^-09 M

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Answer 2

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