Question

15 A uniform ladder of mass m and length L leans against a smooth wall, making an angle with respect to the ground. The dirt exerts a normal force and a frictional force on the ladder, producing a force vector with magnitude Fi at an angle o with respect to the ground. Since the wall is smooth, it exerts only a normal force on the ladder; let its magnitude be F2. (a) Explain why o must be greater than 0. No math is needed. (b) Choose any numerical values you like for m and L, and show that the ladder can be in equilibrium (zero torque and zero total force vector for @ = 45.00° and 6 = 63.43º.

newtonian mechanics only pls thnx

Answer 1

(a) For equilibrium rotational torque a boutany point must be zero. Here, there are three forces F2,mg and resultant (N&F,)F,. the line of all three forces must passes through a single point. Torque about O will be zero to satisify above condition. F, Must be above rod (b) For 0 = 45° and 963.43° f, = F, ---(1) N = mg---(2) Torque about point A mg =cos 8 = F,l sin to = me $= mg x2 mg Ø = 63.43°