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(10%) Problem 9: A point charge Q-4.6 nC is located at the origin. A cylinder of radius R- 0.55 m is concentric with the z-axis with the top of the cylinder at height H1- 0.45 m above the origin and the bottom of the cylinder at height H2045 m below the origin. Refer to the figure. The y-axis points into the screen Z-axis X-axis Otheexpertta.com 20% Part (a) Calculate the electric flux passing out through the top surface in units of N·m2/C Grade Summary Deductions Potential 0% 100% sinO tan T coso cotan asi acosO atan acotan) sinhO cosh tanh cotanhO Submissions Attempts remaining (4% per attempt) detailed view 0 Degrees O Radians Submit Hint I give up!20% Part (b) Calculate the electric flux passing out through the bottom surface in units of N.m2/c. Grade Summary Deductions Potential 100% 0% coso tan 7 89 4 5 6 Submissions sin0 cotan asi acosO atan acotan sinh coshO tanhO cotanho+ Attempts remaining: 5 (4% per attempt) detailed view 0 Degrees ORadians Submit Hint I give up!20% Part (c) Calculate the electric flux passing out through the side surface in units of N·m-/C Grade Summary Deductions Potential 0% 100% sinO tan T coso cotan asi acosO atan acotan) sinhO cosh tanh cotanhO Submissions Attempts remaining (4% per attempt) detailed view 0 Degrees O Radians Submit Hint I give up!20% Part (d) Sum the fluxes passing out through all three surfaces of the cylinder to determine the total flux from the cylinder in units of Nem2/C. Grade Summa Deductions Potential 0% 100% sinO tan T coso cotan asin acoso atan acotan) sinhO cosh) tanh cotanhO Submissions Attempts remaining (4% per attempt) detailed view Al 0 Degrees O Radians Submit I give up!20% Part (e) Use Gausss Law to determine the total flux from the cylinder in Nem2/C. Grade Summa Deductions Potential 0% 100% Submissions Attempts remaining: 5 (4% per attempt) detailed view sinO coso cotan asi acosO atan acotan) sinhO cosh tanh cotanhO 0 Degrees O Radians Submit I give up!Please show all work !!

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Answer #1

. a) For Top Surface; losa = B = Hi H TH2R² = 0.6338 Formula for Flury = Q 11-600) = 4.6 X10-9 11-0.6338) 1 Flux = 95.17 Nm²

d) Total Sum = 2x95:17 + 329.43 1=519.77 Nm3/ z e) using Gausss Lane Y = Qin = 4.6X10-9 8.85X10-12 Flux = 519.774 Nm² <

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