Question

4. Given the following UNBALANCED equation: Fe + Ss --> FeS What type of reaction is this? Is it also a redox reaction? If so, which starting mat reduced? a. What mass of iron is needed to react with 4.00 moles of sulfur (Sx)? b. What mass of iron is needed to react with 16,0 grams of sulfur? How many grams of Fes are produced? 5. For the following balanced reaction for the formation of glucose: 6 CO2 +6H20 → CH,206 +602 a. If you started with 125 g of carbon dioxide and excess water, how many grams of glucose could you get? b. If you started with 148 g of water and excess carbon dioxide, how many grams of glucose could you get? c. If you performed this reaction and the theoretical yield (what you calculate based on amount of reactants weighed out) was 85.22g, but the product you actually obtained weighed only 51.34g, what is the % yield for the reaction?

Answer 1

(4) Unbalanced reaction is a e + So - Fes Balanced reaction 8 Fe + Sg 8 Fes oxidation No Fe So = o = o In Fc S Fe= 5 = - -2 In this reaction oxidation both are & fe and occuring Reduction So it'x & S Redox reaction is reduced and Sulphur Molas mass of fe= 55.84 S82x32 = 256 Fes=55.84 at 2 = 87.84 -

8fc + 58 ~ 8 Fes I mole 4 mole Sg so ² 8 mole fe- Ž 4x8 molefe Ē 32 mole fe = 324 55.84 g fe = 1786.88 g Fc

I mole Sq Ž 8 mole fe 256 g Sg Ē 8x 55.84 fe i 446-72 g Fe 16 g So 446.72 x 16 9 Fe ² 27.92 g Fe 2.56 Ofes Ē Sfe 1 mole fes & 87.84 g FeS I mole fe § 55.84 g fe than 27.92 ge = 8 t.sy x 27.92 55.84 g Fes E 43.92 g FS produced

С СО2 + 6H, о. — CHI, O + co, Molar Mais 44 of more 18 lmor 180 g/mol I 6 Mole 6 хич 8 12 5 7 CO2 Co, CO2 & 1 mole (o Haz oo 18o 2 << Иr 04 = 18• х12 5 2 сеп 294 Gхчч = 8Г. 2272 2 СИno Prdua (b) | 6 mole 18х6 1ча 2 H2O И0 H2O = = = 1 mole Co Hizor 18o 8 С И,206 189 хуча 8 <<H294 18 X4 = 246 64 46 8 CH2 06 | 7 yild = H xleo = 51.3ч хое - 6ок 24ч У theoretical 85.22