Question

Suppose the mean heigh of women age 20 years or older n a ce ar country is 62.2 inches. One hundred random selected women in a certa city had a mean height of 5 T inches. A he % significance provide sufficient evidence to conclude that the mean height of women in the city differs from the national mean? Assume that the population standard deviation of the heights of women in the city is 3.7 inches. e data Set up the hypotheses for the one-mean z-test. Ho: μ The test statistic is z Round to two decimal places as needed.) Identify the critic al value(s). Select the correct choice below and fill in the answer box within your choice (Round to three decimal places as needed) O A. The critical values are a 12-+ O B. The critical value is-4° O C. The critical value is zg- the null hypothesis. The data V sufficient evidence to conclude that the average height of women in the city is the average height of women in the country.

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null hypothesis:Ho Alternate Hypothesis:Ha 62.2 62.2 for 0.1 level with two tailed test, critical value of Decision rule: 1.645 reject Ho if absolute value of test statistic z| >1.645 population mean sample mean sample size population std deviation 62.2 61.70 100.00 3.70 μέ x= standard errror of means σ -σ//ns 0.3700 test statistic z =(X-μ)/σ,- -1.351

for hypothesis:

null hypothesis:Ho μ = 62.2
Alternate Hypothesis:Ha μ 62.2

test statistic z=-1.35

option A is correct . the critical values are -/+ 1.645

fail to reject null hypothesis, the data does not provide sufficient ,,,,,,,in the city is different from the average,,,,,,,,

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