Question

can you use pictures when you solve it to help me undarstand

A right-angle prism is constructed of plexiglass, having an index of refraction equal to 1.55. A laser is oriented such that the light emitted travels perfectly horizontal and is aimed such that the light is incident on the prism. 30.0° (a) If the light is incident from the left side of the prism, determine which surface the light emerges and what is the refraction angle (with respect to the surface it emerges from). (b) If the light is incident from the right side of the prism, determine which surface the light emerges and what is the refraction angle (with respect to the surface it emerges from).

Answer 1

Here angle of incidence te= 60° if angle of refraction is r o then sinh - 1.55 230 sinn Jav sinya Sinbo -0.5587 oy Y, = sin(O.S 507)=34" for sinx = 0 Now ly = 180-(4+120) = 180-(34 #22) = 26° Now sini = 1 or Sint = 1.55x Sin 26= 0.67947 I Sink 1.55 a Lov 2 = sint(0.67947) = 42.8° 6 Here i= 60° a or I sini. T Simm 1.55 + or sing, iss sinto x Y = Siri! (1.55 X sin 60) Ozon hoe - Sini!(1.3423) not posible it means there is total internal reflection 72 so now is = 90-60=300 hence Sines = sink I or Sin/22 1.55x simiz - again this is not posible, raya go on total internal reflection.. Now the emergont ray is perpendicular to the the surface it emerges. Sinn 1.53