Imagine a beaker with octanol layered on top of water. Acetic acid (CH3COOH) dissolves partially in both the octanol and water.
CH3COOH (aq) <-> H+ (aq) + CH3COO− (aq) Ka = 1.8×10-4, pKa = 4.8
CH3COOH (aq) <-> CH3COOH (octanol) KOW = 0.60
Which of the scenarios would result in the largest concentration of acetic acid in water?
Acetic acid is better soluble in octanol when it is un-ionized fo due to the long chain of octanol.
Now, the partition coefficient dictates that acetic acid has lesser quantity in octanol in un-ionized form.
Addition of base in water will ionize acetic acid and it will drain the acetic acid that was present in octanol.
By this largest quantity of acetic acid in water can result.
Imagine a beaker with octanol layered on top of water. Acetic acid (CH3COOH) dissolves partially in...
At equilibrium, acetic acid (CH3COOH) partially dissociates into a proton (H+) and the acetate ion (CH3COO-). An equilibrium mixture contains 0.0990 M acetic acid, 1.33×10-3M acetate, and 1.33×10-3M proton. What is the value of Kc for this reaction?
3. Acetic acid, (CH3COOH) is the component in vinegar that gives it its acidity. It is a weak acid and only partly ionizes when mixed with water according to the following chemical reaction: ????3???????? + ??2?? ? ??3??+ + ????3??????- Write down the expression for the reaction quotient when acetic acid is mixed with water as shown above. if at equilibrium the concentration of CH3COOH is 0.5 M, CH3COO- is 0.4 M and H+ is 1.9 x 10-5, calculate the...
*2.4 Consider a 1M water-solution of acetic acid. a) Given the dissociation constant of acetic acid, K=1.75*10--M, calculate the concentration of non-dissociated acetic acid at equilibrium. Hint The dissociation process is described as a first order process relative to each of the components: CH3COOH CH3COO- + H+
10.00mL of 0.184 M acetic acid(CH3COOH) is titrated with 0.100
M KOH. Ka = 1.80x10^-5. Any help would be much appreciated and a
thumbs up for the help...
2. Complete the ICE table below at this point in the titration. Be sure your Change and Equilibrium lines include the variable "x". Do not calculate "x" for this question. Note: the x must be lowercase. H*(aq) CH3COO (aq) CHнсоонаq) Initial concentration (M) 0 0 Change in concentration (M) -X +X +X...
4. A solution is made by dissolving 15.00 grams of acetic acid and 3.25 grams of sodium acetate in 500.00 mL of water. What is the pH of the solution? The K, of acetic acid is 1.8 x 10. (Hints: First convert grams to mol and then determine the molarity of acetic acid and sodium acetate, ...) 5. What is the pH of a 2.50 molar solution of NHCl(aq)? The Ko for NH, is 1.8 x 105. 6. A certain...
12. Given that Ka = 1.8 x 10- for acetic acid. in order for an acetic acid solution to have a pH of 3.50, its molar concentration must be a. 5.7 x 10-3 M b. 5.6 x 10-3M c. 3.2 x 10-4M d. 2.3 x 10-M 13. If enough base is added to a solution to cause the pH to increase from 7.50 to 8.50, this means that А a. [OH-] increases by a factor of 10 b. [H'] increases...
1. 200 mL of an aqueous solution contains 0.030 M
concentrations of both Pb2+ and Ag+. If 100
mL of 6.0 x 10-2 M NaCl is added to this solution will a
precipitate form? If so, what will the
precipitate be? The Ksp values for PbCl2 and AgCl are 1.7 x
10-5 and 1.8 x 10-10] 2. Which of the following is the expression
for the solubility product of Ba3(AsO4)2? 3. The pKa of a weak acid
is 6.50. What...
1) Which one of the following is a Bronsted-Lowry acid? A) (CH3)3NH+ B) CH3COOH C) HNO2 D) all of the above 2) Which one of the following statements regarding Kw is false? A) pKw is 14.00 at 25 °C. B) The value of Kw is always 1.0 × 10-14. C) Kw changes with temperature. D) The value of Kw shows that water is a weak acid. 3) The Ka of benzoic acid is 6.30 × 10-5. The pH of a...
1. A comic book villain is holding you at gun point and is making you drink a sample of acid. She gives you a beaker with 100ml of a strong acid with pH=5. She also gives you a beaker of a strong base with a pH=10. You can add as much of the strong base to the strong acid as you want, and you must then drink the solution. You'd be best off trying to make the solution neutral before...
How would we find the net ionic equation for this?
For part 4, I mean.
Obtain about 15 ml. of 1.0 M acetic acid in a clean, dry, small plastic beaker. Measure 5.00 mL of the 1.0 M CH,COOH solution in a 10-mL graduated cylinder and transfer it to a 50-mL graduated cylinder. Add enough distilled water to have a total volume of 50.0 mL and mix it thoroughly. The result is a 0.10 M CH,COOH solution. Note and record...