Question

5. A double slit experiment with d=0.025 mm uses 600 nm light. What is the spacing between adjacent bright fringes on a screen 75 cm away?

Answer 1

Given data,

d = 0.025 mm

= 0.025 x 10^-3 m

Wavelength, $\lambda$ = 600 nm

= 600 x 10^-9 m

L = 75 cm

= 75 x 10^-2 m

Let us consider,

spacing of bright ( x) = $\lambda$ L/ d

= ( 600 x 10^-9)( 75 x 10^-2) / (0.025 x 10^-3)

= 0.018 m

= 18 mm