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Given an exponential distribution with 2 = 10, what is the probability that the arrival time is a. less than X=0.1? b. greate

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Answer #1

X ̴ exp (λ = 1 / 10 = 0.1 )

P ( X < x ) = 1 - e(-λ* x)

Part a)
P ( X < 0.1 ) =1 - e^{(-0.01)} = 0.0100


Part b)
P ( X > 0.1 ) = 1 - ( 1 - e^{(- 0.01)}) = 0.9900


Part c)
P ( 0.1 < X < 0.2 ) = P ( X < 0.2 ) - P ( X < 0.1 )
P ( X < 0.1 ) = 1 - e^{(-0.01)} = 0.01
P ( X < 0.2 ) = 1 - e^{(-0.02)} = 0.0198
P ( 0.1 < X < 0.2 ) = 0.0198 - 0.01
P ( 0.1 < X < 0.2 ) = 0.0099

Part d)

less than x = 0.01 or greater than x = 0.2

P ( 0.1 < X) or P ( X > 0.2 ) = 1 - P ( 0.1 < X < 0.2 ) = 1 - 0.0099 = 0.9901

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