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Two reactions and their equilibrium constants are given. A + 2B= 2C Ki = 2.93 2C= D K2 = 0.218 Calculate the value of the equ
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Answer #1

K = 1.57

Given 20 A + 2B - 20 - x = 2.93 kg = 0.218 Reverse reaction o 20 A + 2B ke- 12 R = [A] [B]2 [c72 toz - [A] [872 Lor Reverse r

Given en D = = k A + 2B LAI (B72 [D] Thus required equis same as derived egn- (K = 1.57]

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