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please provide an explanation for your answer.

PLEASE SHOW WORK TO GET FULL UI Problem 2) This problem two independent parts a) and b) a) The number of cars arriving at a fb) The time to failure of a component in an electronic device has an exponential distribution with a median of four hours. Ca

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Answer #1

a)

expected number of cars in 30 minutes =8*30/60 =4

therefore P(fewer than 2 cards) =P(X<=1 )=P(X=0)+P(X=1)=e-4*40/0!+e-4*41/1!=0.0916

b)

here as median =ln(2)/\lambda =4

therefore \lambda =ln(2)/4

P(X>5 )=e-\lambdax =e-ln(2)*5/4 =(1/2)5.4 =0.4204 ~ 0.42 option (iv) is correct

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