Question

How many oxygen atoms are there in 10.0 g of Platinum(III) sulfate?

Answer 1

Given - 10.09 of Platinum (11) Sulfate [Pty (504)3] We know- - Weight of Substance taken (W)_ No. of moles (n) = – . Molecular weight of substance (M) Hene, W of Pł, (S04)3 = 10.08 M of Pty (504)3 = 678.2 g/more . no. of moles (n.) of Pt₂SO4)₂ = W -- 10 g 678.2 g mote = 0.0147 mose

int Also we know that - In One more of any substance has 6.023 x 1023 molecul :: No. of molecules present in 0.0147 mole of Pt, (S04), in = 0.0147 x 6.023X1023 = 8.85 x 1021

Now, In One Pt, (SO4)3 molecule there are (3*4)=12 oxygen atom present. : No. Of oxygen atoms present in 8.85 x 1021 molecuses of Pły S04), is = 12 (8.85x1021) = 1.062 x 1023 :. No. of oxygen som present in 10.0 g g Pt₂(SO4)2 i's 1.062 x1023. Ans.