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Balance the reaction below and determine the #electrons (in mol) involved in the reaction. a. CH4 + O2 -> b. C2H6 + 02 -> C.

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Combution Reaction of Hydrocarbon. | Сн, (х + 2) о, —, z o. + ho/ а) они + 0 - 0, + но хэл у= Ч сну + (1 + 4) - 1, + + H,0 сн1 ② @ ② Cate + 50 24 Ho & 13 0 CSHA & 80 lo – 30 – 8 0 - scoa + 4H2O + 10 H2O + 6H2O 1 1 2C6H14 & 190₂ 12 co2 & 14 H₂O are g

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