Question

Study Example 8.1 on page 321. Then, calculate the molarity of a solution made by adding 5.57 g of CaCl2 to enough water to create a solution with a total volume of 2.50 L. Enter only a numerical value in the correct number of significant figures. Use the Periodic Table that is part of your exam to calculate molar mass. Do not enter units in the answer box, but know that the symbol for the unit of this calculation is M.

Answer 1

Ans- Calculation of molareity of solution - Mass of Calle (solute) = 5579 Volume of solution = dosol Molecular mass of Cally = 40.0789 mol-' + 2 x 35.453g mo! = 40.078 + 70.906 = 110.984gmord Molarity = Number of moles of Calla Volume of solution CinL) No. of moles of calle = Mass of calle - 5.579 Molecular mass 10.984 gmail = 0.0501 Molauity = 0.0501 mol 2.50 L = 0.02 mol L The molarity of the solution is 0.02 M

Ans Calculation of mass of coppen (II) nitseade cin goans) Molarity of Cu(NO,), solution = 0.612 M. Volume of Solution - 100 mL = 0.14 Molecular mass of Cu(NO3)2 = 63.55 gmon't 2 [14 gmoltt L 3x16 gmolly = 63.55+ 2 [147 48] = 63.55+2 [62] = 63.55 +124 - 187.55 gmoly Molarity = No. of moles of Culo) Volume of solution (In2) Molauity = Mass of Cu(NO) Molecular Maxs of tulos), Volume 0.612 M = Mass of Cu(NO3)2 187.55 g mort x 0.12 Mars of Cu(NO3)2 = 11.4780 g | Mass of cules)= 11.4897 Mass of cu(NO3)2 for preparation of 10ome of 0.612 m G Nos? solution is 11.48g