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1. Label each set of chemically equivalent protons, using a for the set that will be at the lowest frequency in the H NMR spe
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Solution:

The numbering and multiplicities are given below.

CH₃-CHNO2 a= Doublet b-amarlet b CH₂ CH₂OCHz c 4 a = Triplet b = 12 peaks e = Triplet d-singlet filis - Hochenzauz a ca Cuzb

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