Hess's Law problem, find change in heat
2NH3 + 1/2O2 --> N2H4 + 3H2O
broken into
1. NH3 + 3N2O --> 4N2 + 3H2O
2. N2O + 3H2 --> N2H4 + H2O
3. N2H4 + O2 --> N2 + 2H2O
4. H2 + 1/2O2 -- H20
Hess's Law problem, find change in heat 2NH3 + 1/2O2 --> N2H4 + 3H2O broken into...
(ii) Calculate AH° for the reaction N2H4(1) + O2(g) → N2(g) + 2H2O(1) using the data given below: 2NH3(g) + 3N2O(g) → 4N2(g) + 3H2O(1) N2O(g) + 3H2(g) → N2H4(l) + H2O(1) 2NH3(g) + O2(g) → N2H4(1) + H2O(1) H2(g) + 1/2O2(g) → H2O(1) AH° = -1010. kJ AH° = -317 kJ AH° = -143 kJ AH° = -286 kJ
Determine the heat involved in the combustion of liquid hydrazine by using the following reactions. Use the balanced equation determined on the previous slide to begin. 2NH3(g) + 3N2O(g) → 4N2(g) + 3H2O(ℓ) ΔH° = –1013 kJ/mol N2O(g) + 3H2(g) → N2H4(ℓ) + H2O(ℓ) ΔH° = –317 kJ/mol 2NH3(g) + ½O2(g) → N2H4(ℓ) + H2O(ℓ) ΔH° = –142.9 kJ/mol H2(g) + ½ O2(g) → H2O(ℓ) ΔH° = –285.8 kJ/mol Launching a small spacecraft to study Jupiter required approximately 28 million...
Consider the two reactions. 2NH3(g) + 3N2O(g) -> 4N2(g) + 3H2O(l) Delta H = -1010kj 4NH3(g) + 3O2(g) -> 2N2(g) + 6H2O(l) Delta H = 1531 Using these two reactions, calculate and enter the enthalpy change for the reaction below. N2(g)+1/2O2(g)⟶N2O(g)
Calculate AH for the reaction N2H4(0) + O2(g) → N2(g) + 2 H2O(1) given the following data: Equation AH (kJ) 2 NH3(g) + 3 N2O(g) → 4 N2(g) + 3 H2O(l) -1010 N2O(g) + 3 H2(g) → N2H4(1) +H2O(1) -317 2 NH3(g) + 1202(g) → N2H4(1) + H20(1) -143 H2(g) + 1202(g) → H2O(H -286 AH=
(1) Find the H for the reaction below, given the following reactions and subsequent H values: 2CO2(g) + H2O(g) → C2H2(g) + 5/202(g) CH2(g) + 2H2(g) → CHg) H2O(g) - H2(g) + 1/20, (g) C2H6(g) + 7/202(g) → 2CO2(g) + 3H2O(g) answer - 235 kJ H =-94.5 kJ H =71.2 kJ H --283 kJ (2) Find the H for the reaction below, given the following reactions and subsequent H values: N2H4(I) + H2(g) + 2NH3(g) N2H4(1) + CH4O(1) - CH2O(g)...
1. From the following equations and enthalpies, determine the molar heat of formation of HNO2(aq) . NH4NO2(aq) → N2(g) + 2H2O(l) ∆H = -320.1 kJ NH3(aq) + HNO2(aq) → NH4NO2(aq) ∆H = -37.7 kJ 2NH3(aq) → N2(g) + 3H2(g) ∆H = +169.9 kJ H2(g) + 1/2 O2(g) → H2O(l) ∆H = -285.8 kJ
Using the standard molar heat of combustion of hydrogen, methane, and ethane (given below), find the enthalpy change for 2CH4(g) → C2H6(g) + H2(g) H2 + ½ O2 → H2O ΔHo = -285.8 kJ CH4 + 2O2 → CO2 + 2H2O ΔHo = -890.4 kJ C2H6 + (7/2)O2 → 2CO2 + 3H2O ΔHo = -1559.9 kJ
Use Hess’s Law to find the standard enthalpy change for the reaction CO2(g) → C(s) + O2(g) using only the following information. Show all your work, including any equations you use to obtain your answer and showing clearly how you obtained that answer. (3 pts.) H2O(l) → H2(g) + 1/2O2(g) C2H6(g) → 2C(s)+ 3H2(g) 2CO2(g) + 3H2O(l) → C 2H6(g) + 7/2O2(g) ∆Ho (kJ) 643 kJ 190.6kJ 3511.1 kJ
Calculate the standard reaction enthalpy for the reaction N2H4(ℓ) + H2(g) → 2 NH3(g) given N2H4(ℓ) + O2(g) → N2(g) + 2H2O(g) ∆H ◦ = −543 kJ · mol−1 2 H2(g) + O2(g) → 2 H2O(g) ∆H◦ = −484 kJ · mol−1 N2(g) + 3 H2(g) → 2 NH3(g) ∆H◦ = −92.2 kJ · mol−1 1.) −243 kJ · mol−1 2.) −59 kJ · mol−1 3.) −935 kJ · mol−1 4.) −151 kJ · mol−1 5.) −1119 kJ · mol−1
3. The second part of the experiment uses Hess's Law, to determine a heat of reaction that would be difficult to measure directly, the heat of combustion of either calcium or magnesium metal. Show how the equation for the combustion reaction (4) may be obtained by combining equations 1 - 3 below algebraically. (M signifies either calcium or magnesium.) Note: Since M is a general symbol the actual heat cannot be determined. You only need to show how the equations...