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Problem 2: _This platform can be considered a uniform plank of mass 200. kg and length 3.00 m. A 50.0 kg mass is 75.0 cm from
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Answer #1

The system is at rest Ex = 0 {fyzo Ezzo {fy = 0 50g + 200g = Fit F Fit F2 = 250g G r Iz=0 Taking torque about A 6(2.25) – 200

F + Ez = 250g 3F - F2 = 200g 46 = 450g Fi= 112.5g F = 250g - 112.59 = 137.59

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