Question

Calculate:

Part A) [H+] for [OH−]=3.5×10^-4 M Express your answer using two significant figures.

Part B) [H+] for [OH−] =8.4×10^-9 M Express your answer using two significant figures.

Part C) Calculate [H+] for a solution in which [OH−] is 100 times greater than [H+].

Please show how you solved it, thanks!

Part A Calculate (H+] for Express your answer using two significant figures. VO AED ? Submit Previous Answers Request Answer X Incorrect; Try Again; 5 attempts remaining The ion-product constant of water, k 1 x 10-14, can be used to solve for (H+).

Answer 1

part A Cor = 3-5X10M CHPJ: 1014 CoH] 3.5x109 CH+z=0.2857 x 10 CH+] = 2.9820 M m part -B Colt] = 8.4 Xlory 47. ro'y 8.48 107 - = 0.1190 X 0 M Cat 7 = 1.2410 - V parte Cole z 100 Cat] =) COH)= 1000lt] Let är be the molarity of Cht] Cat] =[ori) = 1x10 e fol neutral solution criven solutions are acidic, baric & neutral kwa Cht] [OF]= 1x1014 = 'CH] 100cht] = 1x104 -) Chtje 1x 1016 =) CH+]=ſixol6 = 1x108=10xio