Solution :
Given that ,
mean =
= 250
standard deviation =
=20
P(x < 214 ) = P[(x -
) /
< (214-220) /20 ]
= P(z < -0.30 )
= 0.0013
probability =0.0013
b)
P(x > 294) = 1 - p( x< 294 )
=1- p [(x -
) /
< (294-220) /20 ]
=1- P(z < 3.7)
= 1 - 0.9999 = 0.0001
probability = 0.0001
c)
P( 200< x < 290) = P[(200-220)/20 ) < (x -
) /
<
(290-220) /20 ) ]
= P(-1 < z < 3.5 )
= P(z < 3.5) - P(z < -1 )
Using standard normal table
= 0.9998- 0.1587 = 0.8411
Probability = 0.8411
Length of metal strips produced by a machine process are normally distributed with a mean length...
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