what is the ksp expression for a solution of Ca3(PO4)2?
At equilibrium:
Ca3(PO4)2 <----> 3 Ca2+ + 2 PO43-
3s 2s
Ksp = [Ca2+]^3[PO43-]^2
=(3s)^3*(2s)^2
= 108(s)^5
Answer: Ksp = [Ca2+]^3[PO43-]^2
Calculate the solubility of Ca3(PO4)2 in a solution containing 0.0539 M Na3PO4. Ksp=2.0*10^-29 for Ca3(PO4)2
Calculate the equilibrium concentration of PO43- in a saturated aqueous solution of Ca3(PO4)2. The Ksp value of Ca3(PO4)2 is 1.0 x 10-25.
what is the molar solubility of Ca2+ in a 1.00 M aqueous solution of Ca3(PO4)2 (Ksp for calcium phosphate is 2.0 x 10^-29)
If the concentration of phosphate ions ([PO43-1) in a saturated solution of Ca3(PO4)2 is known, which expression should be used to calculate the solubility product constant (Ksp) for Ca3(PO4)2? Kp - 8 [PO43-15/27 Ksp - 3(PO4"-1/2 Ksp = 27 (PO43-1978 Ksp -9 [PO43-1514 Kup 4(PO43-119
Determine the molar solubility for each of the following. a.) Ca3(PO4)2 given Ksp = 2.0 x 10-29 b.) Ca3(PO4)2 in a solution containing 0.010 M Ca(OH)2 c.) Ca3(PO4)2 in a solution containing 0.010 M of K2PO4
Calculate the equilibrium concentration of Ca2+ in a saturated aqueous solution of Ca3(PO4)2. The Ksp value is 1.0 x 10-25.
The Ksp of Ca3(PO4)2 is 1x 10-33. What is the solubility in moles per liter (mol/L) of Ca3(PO4)2 (s) in a 0.01 M Ca(NO3)2 (aq) solution? (Note: The molar mass of Ca3(PO4)2 is not needed in this problem, which asks for moles per L.) a. 3.2 x 10-14 mol/L b.3.0 x 10-15 mol/L c. 9.8 x 10 mol/L d. 1.6 x 10-14 mol/L e. 5.0 x 10-32 mol/L
the crc handbook gives the solubility of ca3(po4)2 at 25 c as .0012g/100ml . determine the molar solubility of ca3(po4)2 . this is the molarity of saturated solution . and determine ksp of ca3(po4)2
Excess Ca3(PO4)2 is added to a beaker of water. At equilibrium, the PO4 concentration is 1.8 X 10^-6 M. What is the Ksp for Ca3(PO4)2? Please show all work
The solubility of Ca3(PO4)2 (molar mass = 310 g/mol) in water is 0.065 g/L. The Ksp for Ca3(PO4)2 is ______ (scientific notation with 2 sig fig, such as 3.5e-9)